Can you explain the minimum of 9 bits needed to send a calendar date (mm/dd)?

# Lesson 1.6 Bits needed for calendar date

In order to solve the minimum number of bits needed for the month and day we think about the largest both of those values can be.

The latest month is December which is the number 12 or **1100** in binary.

The longest month has 31 days which is **11111** in binary.

So December 31st or **12/31** could be **1100 / 11111**.

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Thank you. At first, I was seeing it as one number 1231 and not putting in the / for separation. Makes perfect sense! Thanks.